Which of the lines x1 and x2 is perpendicular to the plane with general equation 2x - 2y + 2z = 3?
x1 = (0, -1, 4) + t(1, -1, 1)
x2 = (5, 1, 0) + t(2, 0, 1)
Answer is x1 ...
I tried dot product of (1, -1, 1) dot (2, -2, 2) to try get 0 (which would mean they are perpendicular) ... but it gives 6....
x1 = (0, -1, 4) + t(1, -1, 1)
x2 = (5, 1, 0) + t(2, 0, 1)
Answer is x1 ...
I tried dot product of (1, -1, 1) dot (2, -2, 2) to try get 0 (which would mean they are perpendicular) ... but it gives 6....




Comment